Advertisements
Advertisements
प्रश्न
The distance of the point (–6, 8) from x-axis is ______.
विकल्प
6 units
– 6 units
8 units
10 units
Advertisements
उत्तर
The distance of the point (–6, 8) from x-axis is 8 units.
Explanation:
The distance of the point (x, y) from x-axis is y-coordinate
∴ The distance of the point (–6, 8) from x-axis is 8 units.
संबंधित प्रश्न
Name the quadrilateral formed, if any, by the following points, and given reasons for your answers:
A(-3, 5) B(3, 1), C (0, 3), D(-1, -4)
The line joining the points (2, 1) and (5, −8) is trisected at the points P and Q. If point P lies on the line 2x − y + k = 0. Find the value of k.
If the points p (x, y) is point equidistant from the points A (5, 1)and B (–1, 5), Prove that 3x = 2y
The co-ordinates of point A and B are 4 and -8 respectively. Find d(A, B).
Mark the correct alternative in each of the following:
The point of intersect of the coordinate axes is
Find the area of a parallelogram ABCD if three of its vertices are A(2, 4), B(2 + \[\sqrt{3}\] , 5) and C(2, 6).
If the points A(−2, 1), B(a, b) and C(4, −1) ae collinear and a − b = 1, find the values of aand b.
If P is a point on x-axis such that its distance from the origin is 3 units, then the coordinates of a point Q on OY such that OP = OQ, are
Points (1, – 1), (2, – 2), (4, – 5), (– 3, – 4) ______.
Point (3, 0) lies in the first quadrant.
