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Question
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
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Solution
Force of gravity:
`F = (Gm_1m_2)/r^2`
It is given that r2 = 2r1
`:.F_2/F_1 = r_1^2/r_2^2 = r_1^2/(4r_1^2) = 1/4`
`:. F_2 = 1/4 F_1`
Therefore, the force of gravity is reduced four times.
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