Advertisements
Advertisements
Question
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
Advertisements
Solution
Force of gravity:
`F = (Gm_1m_2)/r^2`
It is given that r2 = 2r1
`:.F_2/F_1 = r_1^2/r_2^2 = r_1^2/(4r_1^2) = 1/4`
`:. F_2 = 1/4 F_1`
Therefore, the force of gravity is reduced four times.
APPEARS IN
RELATED QUESTIONS
The figure shows three pieces of cardboard of uniform thickness cut into three different shapes. On each diagram draw two lines to indicate the position of the centre of gravity G.
A right-angled triangle cardboard piece is placed as shown in fig. 7. Redraw the diagram showing the relative position of the vertices of the triangle when it is suspended by a pin from the hole A. Explain why the position changes?
Give scientific reason for the following:
There are chances of toppling when a truck takes a sharp turn especially when it is not fully loaded
Explain why a ship loaded with light goods is more liable to be overturned than the one loaded with heavy goods.
Explain why Standing passengers are not allowed on the upper deck of a double-decker bus.
A metal sphere is hanging from the ceiling of a vehicle. If the vehicle is moving along the horizontal road with uniform acceleration 'a' then the suspended thread of the sphere gets inclined to the vertical at an angle 'θ'. The value of acceleration 'a' is (g = acceleration due to gravity) ______.
Mention the real-life applications of the center of gravity.
In a non-uniform gravitational field, how does the Centre of Gravity relate to the Centre of Mass?
