Advertisements
Advertisements
प्रश्न
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
Advertisements
उत्तर
Force of gravity:
`F = (Gm_1m_2)/r^2`
It is given that r2 = 2r1
`:.F_2/F_1 = r_1^2/r_2^2 = r_1^2/(4r_1^2) = 1/4`
`:. F_2 = 1/4 F_1`
Therefore, the force of gravity is reduced four times.
APPEARS IN
संबंधित प्रश्न
Give an example of a non-contact force which is always of attractive nature
On what factor does the position of the center of gravity of a body depend?
What is the position of the centre of gravity of a rectangular lamina?
Fig. shows the dimensions of an acute angled triangle. By geometrical construction mark the C.G. of the triangle.

Give scientific reason for the following:
There are chances of toppling when a truck takes a sharp turn especially when it is not fully loaded
Explain why One leans forward while climbing up a hill.
Mention the real-life applications of the center of gravity.
Why is it beneficial for engineers to design tall structures with a low Centre of Gravity?
