Advertisements
Advertisements
प्रश्न
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
Advertisements
उत्तर
Force of gravity:
`F = (Gm_1m_2)/r^2`
It is given that r2 = 2r1
`:.F_2/F_1 = r_1^2/r_2^2 = r_1^2/(4r_1^2) = 1/4`
`:. F_2 = 1/4 F_1`
Therefore, the force of gravity is reduced four times.
APPEARS IN
संबंधित प्रश्न
A square cardboard is suspended by passing a pin through a narrow hole at its one corner. Draw a diagram to show its rest position. In the diagram, mark the point of suspension by the letter S and the centre of gravity by the letter G.
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.

Give scientific reason for the following:
In a doubled decker bus passengers are not allowed to stand in the upper deck.
The centre of gravity of a hollow cone of height h is at distance x from its vertex where the value of x is ______.
Answer the following question.
Why do we need to know the center of mass of an object? For which objects, its position may differ from that of the center of gravity?
Write about the experiment to find the centre of gravity of the irregularly shaped plate.
A metal sphere is hanging from the ceiling of a vehicle. If the vehicle is moving along the horizontal road with uniform acceleration 'a' then the suspended thread of the sphere gets inclined to the vertical at an angle 'θ'. The value of acceleration 'a' is (g = acceleration due to gravity) ______.
