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प्रश्न
Explain how you will determine experimentally the position of the centre of gravity for a triangular lamina (or a triangular piece of cardboard).
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उत्तर
Take a triangular lamina. Make three fine holes at a, b, and c near the edge of the triangular lamina. Now suspend the given lamina along with a plumb line from hole 'a'. Check that the lamina is free to oscillate about the point of suspension. When the lamina has come to rest, draw a straight line ad along the plumb line. Repeat the experiment by suspending the lamina through hole 'b' and then through hole 'c' for which we get straight lines to be and cf, respectively. It is noticed that the lines ad, be and cf intersect each other at a common point G, which is the position of the centre of gravity of the triangular lamina, i.e., the point of intersection of medians.

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संबंधित प्रश्न
Where is the centre of gravity of a uniform ring situated?
A uniform flat circular rim is balanced on a sharp vertical nail by supporting it at point A, as shown in the figure. Mark the position of the centre of gravity of the rim in the diagram by the letter G.

Can the CG be situated outside the material of the body? Give an example.
Answer the following question.
Why do we need to know the center of mass of an object? For which objects, its position may differ from that of the center of gravity?
In ______ equilibrium, the centre of gravity remains at the same height when it is displaced.
What is centre of gravity ?
Mention the real-life applications of the center of gravity.
A hollow ice cream cone has height 6 cm.
- Where is the position of its center of gravity from the broad base?
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