Advertisements
Advertisements
प्रश्न
Explain how you will determine experimentally the position of the centre of gravity for a triangular lamina (or a triangular piece of cardboard).
Advertisements
उत्तर
Take a triangular lamina. Make three fine holes at a, b, and c near the edge of the triangular lamina. Now suspend the given lamina along with a plumb line from hole 'a'. Check that the lamina is free to oscillate about the point of suspension. When the lamina has come to rest, draw a straight line ad along the plumb line. Repeat the experiment by suspending the lamina through hole 'b' and then through hole 'c' for which we get straight lines to be and cf, respectively. It is noticed that the lines ad, be and cf intersect each other at a common point G, which is the position of the centre of gravity of the triangular lamina, i.e., the point of intersection of medians.
APPEARS IN
संबंधित प्रश्न
The distance between two bodies is doubled. How is the magnitude of the gravitational force between them affected?
A uniform half meter rule balances horizontally on a knife-edge at 29 cm mark when a weight of 20 gf is suspended from one end
1) Draw a diagram of the arrangement
2) What is the weight of the half meter rule?
State a factor on which the position of the centre of gravity of a body depend? Explain your answer with an example.
A uniform flat circular rim is balanced on a sharp vertical nail by supporting it at point A, as shown in the figure. Mark the position of the centre of gravity of the rim in the diagram by the letter G.
Where does the position of centre of gravity lie for a circular lamina?
Explain why a tight rope-walker, often holds a long pole in his hands when in action.
Answer the following question.
Why do we need to know the center of mass of an object? For which objects, its position may differ from that of the center of gravity?
If mean radius of earth is R, its angular velocity is ro and the acceleration due to gravity at the surface of the earth is g, then the cube of the radius of the orbit of satellite will be ____________.
