Advertisements
Advertisements
प्रश्न
Explain how you will determine experimentally the position of the centre of gravity for a triangular lamina (or a triangular piece of cardboard).
Advertisements
उत्तर
Take a triangular lamina. Make three fine holes at a, b, and c near the edge of the triangular lamina. Now suspend the given lamina along with a plumb line from hole 'a'. Check that the lamina is free to oscillate about the point of suspension. When the lamina has come to rest, draw a straight line ad along the plumb line. Repeat the experiment by suspending the lamina through hole 'b' and then through hole 'c' for which we get straight lines to be and cf, respectively. It is noticed that the lines ad, be and cf intersect each other at a common point G, which is the position of the centre of gravity of the triangular lamina, i.e., the point of intersection of medians.

APPEARS IN
संबंधित प्रश्न
What is the weight of a body placed at the centre of the earth?
State a factor on which the position of the centre of gravity of a body depend? Explain your answer with an example.
Following Fig shows piece of cardboard of uniform thickness cut into different shapes. Draw two lines to indicate the position of centre of gravity G.

Fig. shows the dimensions of an acute angled triangle. By geometrical construction mark the C.G. of the triangle.

Even though the Tower of Pisa is leaning through an angle it does not fall.
Explain the term ‘centre of gravity’ of a body.
Answer the following question.
Why do we need to know the center of mass of an object? For which objects, its position may differ from that of the center of gravity?
A metal sphere is hanging from the ceiling of a vehicle. If the vehicle is moving along the horizontal road with uniform acceleration 'a' then the suspended thread of the sphere gets inclined to the vertical at an angle 'θ'. The value of acceleration 'a' is (g = acceleration due to gravity) ______.
