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Question
The distance between points P(–1, 1) and Q(5, –7) is ______.
Options
11 cm
10 cm
5 cm
7 cm
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Solution
The distance between points P(–1, 1) and Q(5, –7) is 10 cm.
Explanation:
Let P(x1, y1) = P(–1, 1) and Q(x2, y2) = Q(5, –7)
Here, x1 = –1, y1 = 1, x2 = 5, y2 = –7
By distance formula,
`d(P, Q) = sqrt((x_2 - x_1)^2 + (y_2 - y_1)^2)`
= `sqrt([5 - (-1)]^2 + (-7 - 1)^2)`
= `sqrt(36 + 64)`
= `sqrt(100)`
= 10 cm
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