Advertisements
Advertisements
Question
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the total clockwise moment about O
Advertisements
Solution
Total clockwise moment about O,
=250 gf x 20 cm= 5000 gf cm
RELATED QUESTIONS
Where can a body execute free vibrations?
Moment of force = force × perpendicular distance of force – from the pivoted point.
How does the effect of force differ when it is applied on a rigid body?
Write the expression for the moment of force about a given axis of rotation.
Calculate the acceleration produced in a body of mass 50 g when acted upon by a force of 20 N.
State one way to reduce the moment of given force about a given axis of rotation.
Give two examples of a couple's actions in our daily life.
A wheel of diameter 3 m is shown in fig. 2 with axle at 0. A force F = 8 N is applied at Q in the direction shown in figure. Calculate the moment of force about:
(i) centre o, and
(ii) point p.
What is meant by the term ‘moment of force’? If the moment of force is assigned a negative sign then will the turning tendency of the force be clockwise or anti-clockwise?
The diagram in Fig shows two forces F1 = 5 N and F2 = 3 N acting at points A and B respectively of a rod pivoted at a point O, such that OA = 2 m and OB = 4 m.
Calculate:
- the moment of force F1 about O.
- the moment of force F2 about O.
- total moment of the two forces about O.
