Advertisements
Advertisements
प्रश्न
The diagram shows a uniform metre rule weighing 100gf, pivoted at its centre O. Two weights 150gf and 250gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm. Calculate :
the total clockwise moment about O

Advertisements
उत्तर
Total clockwise moment about O,
=250 gf x 20 cm= 5000 gf cm
संबंधित प्रश्न
Sleepers are used below the rails.
A spanner of length 10 cm is used to open a nut by applying a minimum force of 5.0 N. Calculate the moment of force required.
What are non-contact forces? Give two example
State the relationship between force, mass and acceleration. Draw graphs showing the relationship between Acceleration and mass for a constant force.
State Newton's third law of motion.
A car of mass 600 kg is moving with a speed of 10 m-1 while a scooter of mass 80 kg is moving with speed of 50 m s-1. which vehicle will require more force to stop it in the (1) same interval of time (2) same distance
Explain the motion of a planet around the sun in a circular path.
Fig. shows a uniform meter scale weighing 100 N pivoted at its centre. Two weights of 500 N and 300 N are hung from the ruler as shown in fig.

(i) Calculate total clockwise and anticlockwise moments.
(ii) Calculate difference in clockwise moment and anticlockwise moment.
(iii) Calculate the distance from O where a 100 N weight should be suspended to balance the meter scale.
In a beam balance when the beam is balanced in a horizontal position, it is in ________ equilibrium.
Calculate the magnitude of the force of a couple, when the arm of the couple is 63 cm and the moment of the couple is 21 Nm.
