Advertisements
Advertisements
प्रश्न
A nut is opened by a wrench of length 20 cm. If the least force required is 2N, find the moment of force needed to loosen the nut.
Advertisements
उत्तर
According to the principle of moments, we have
Moment of load about the fulcrum = Moment of effort about the fulcrum
Load × Load arm = Effort × Effort arm
Given that the effort arm = 20 cm = 0.2 m, the minimum force E = 2 N
Therefore, the moment of load or the moment of force = 0.2 × 2 = 0.4 Nm
The moment of force needed to loosen the nut = 0.4 Nm
APPEARS IN
संबंधित प्रश्न
A force is applied on (i) a non-rigid body and (ii) a rigid body. How does the effect of the force differ in the above two cases?
State the S.I. unit of moment of force.
State the relationship between force, mass and acceleration. Draw graphs showing the relationship between Acceleration and force for a constant mass.
Name and define the S.I. and C.G.S. units of force. How are they related?
State one way to reduce the moment of given force about a given axis of rotation.
The stone of hand flour grinder is provided with a handle near its rim. Give reason.
A steering wheel of diameter 0.5 m is rotated anticlockwise by applying two forces each of magnitude 6 N. Draw a diagram to show the application of forces and calculate the moment of forces applied.
The diagram in the figure shows a uniform metre rule weighing 100 gf, pivoted as its centre O. two weight 150 gf and 250 gf hang from the point A and B respectively of the metre rule such that OA = 40 cm and OB = 20 cm . Calculate
the total anticlockwise moment about o.

Under what condition will a set of gears produce a gain in torque.
The perpendicular distance between the point of application of force and turning point is 1.75 m when a force of 80 N acts on a rigid body. Calculate the moment of force.
