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The Common Difference of an A.P., the Sum of Whose N Terms is Sn, is

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Question

The common difference of an A.P., the sum of whose n terms is Sn, is

Options

  • Sn − 2Sn−1 + Sn−2

  • Sn − 2Sn−1 − Sn−2

  • Sn − Sn−2

  •  Sn − Sn−1

MCQ
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Solution

Here, we are given an A.P. the sum of whose n terms is Sn. So, to calculate the common difference of the A.P, we find two consecutive terms of the A.P.

Now, the nth term of the A.P will be given by the following formula,

`a_n = S_n - S_(n-1) `

Next, we find the (− 1)th term using the same formula,

`a_(n - 1) = S_(n - 1) - S_((n - 1) -1)`

         `=S_(n-1) - S_(n-2)`

Now, the common difference of an A.P. (d) =  ` a_n - a_(n-1)` 

=`(S_n - S_(n-1)) - (S_(n-1) - S_(n - 2))`

=`S_n - S_(n-1) - S_(n-1) +S_(n-2)`

`=S_n - 2 S_(n-1) + S_(n - 2)`

Therefore, `D = S_n - 2S_(n-1) + S_(n -2) `

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Chapter 5: Arithmetic Progressions - Exercise 5.8 [Page 58]

APPEARS IN

R.D. Sharma Mathematics [English] Class 10
Chapter 5 Arithmetic Progressions
Exercise 5.8 | Q 24 | Page 58
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