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Questions
In an AP, given a = 7, a13 = 35, find d and S13.
In an A.P. (with usual notations): given a = 7, a13 = 35, find d and S13.
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Solution
Given that, a = 7, a13 = 35
As an = a + (n − 1) d,
∴ a13 = a + (13 − 1) d
35 = 7 + 12d
35 − 7 = 12d
28 = 12d
d = `28/12`
d = `7/3`
sn = `n/2[a+a_n]`
S13 = `n/2[a+a_13]`
= `13/2[7+35]`
= `(13xx42)/2`
= 13 × 21
= 273
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