Question

The circular scale of a screw gauge has 50 divisions. Its spindle moves by 2 mm on the sleeve, when given four complete rotations calculate

1. pitch
2. least count

Answer 1

Number of circular scale divisions (C.S.D.) = 50
Distance moved by screw (spindle) on sleeve = 2 mm
Number of complete rotations given = 4

(1) Pitch = `"Distance moved by screw on sleeve"/"No. of complete rotations"`

= `(2 "mm")/4`

= 0.5 mm

(2) Pitch = 0.05 cm

Least count = `"Pitch"/"No. of circular scale divisions"`

= `0.05/50`

= 0.001 cm