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Question
The change in internal energy in a reaction when 2kJ of heat is released by the system and 6 kJ of work is done on the system will be ______.
Options
+4 kJ
4kJ
+3 kJ
– 8 kJ
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Solution
The change in internal energy in a reaction when 2kJ of heat is released by the system and 6 kJ of work is done on the system will be +4 kJ.
Explanation:
ΔU = Q + W
= −2 kJ + 6 kJ
= +4kJ
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