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Question
The area of rhombus is `480cm^2` , and one of its diagonal measures 48 cm. Find
(i) the length of the other diagonal,
(ii) the length of each of the sides
(iii) its perimeter
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Solution
(i) Area of a rhombus, =` 1/2xxd_1xxd_2`, Where `d_1 and d_2` are the lengths of the diagonals.
⇒ `480=1/2xx48xxd_2`
⇒`d_2=(480xx2)/48`
⇒ `d_2=20 cm`
∴ Length of the other diagonal=`20cm`
(2) side=`1/2 sqrt(d_1^2-d_2^2)`
= `1/2sqrt(48^2+20^2)`
=`1/2sqrt(2304+400)`
=`1/2sqrt2704`
=`1/2xx52`
=`26 cm`
∴ Length of the side of the rhombus =`26cm`
(iii) Perimeter of the rhombus=`4xx"side"`
=`4xx26`
=`104 cm`
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