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Question
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is ______.
Options
`sqrt(15)` cm2
`sqrt(15/2)` cm2
`2sqrt(15)` cm2
`4sqrt(15)` cm2
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Solution
The area of an isosceles triangle having base 2 cm and the length of one of the equal sides 4 cm, is `underlinebb(sqrt(15) cm^2)`.
Explanation:
a = 2, b = 4, c = 4
`s = (a + b + c)/2`
⇒ `s = (2 + 4 + 4)/2 = 10/2 = 5`
Area (Δ) = `sqrt(s(s - a)(s - b)(s - c))`
⇒ Area (Δ) = `sqrt(5(5 - 2)(5 - 4)(5 - 4))`
⇒ Area (Δ) = `sqrt(5 xx 3 xx 1 xx 1`
⇒ Area (Δ) = `sqrt(15)` cm2
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