Advertisements
Advertisements
Question
The area of an equilateral triangle is (`64xxsqrt3`) cm2. Find the length of each side of the triangle.
Advertisements
Solution
Area of equilateral triangle = `64sqrt3` cm2
Let each side = a
Then, `sqrt3/4"a"^2=64sqrt3`
a2 =`(64sqrt3xx4)/sqrt3=256`
a = (16)2
∴ a = 16 cm
∴ Each side = 16 cm
APPEARS IN
RELATED QUESTIONS
In the figure given below, find the area of shaded region: (All measurements are in cm)

In the figure given below, find the area of shaded region: (All measurements are in cm)

One side of a parallelogram is 20 cm and its distance from the opposite side is 16 cm. Find the area of the parallelogram.
The area of a rhombus is 84 cm2 and its perimeter is 56 cm. Find its height.
The area of a right-angled triangle is 160 cm2. If its one leg is 16 cm long, find the length of the other leg.
Find the base of a triangle whose area is 360 cm2 and height is 24 cm.
The legs of a right-angled triangle are in the ratio 4 : 3 and its area is 4056 cm2. Find the length of its legs.
The diameter of a circle is 20 cm. Taking π = 3.14, find the circumference and its area.
A metal wire, when bent in the form of a square of largest area, encloses an area of 484 cm2. Find the length of the wire. If the same wire is bent to the largest circle, find:
(i) radius of the circle formed.
(ii) area of the circle.
A wire is along the boundary of a circle with a radius of 28 cm. If the same wire is bent in the form of a square, find the area of the square formed.
