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Question
The area of a rhombus is 480 cm2, and one of its diagonals measures 48 cm. Find
(i) the length of the other diagonal,
(ii) the length of each of its sides, and
(iii) its perimeter.
Sum
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Solution
(i) Area of a rhombus, =` 1/2xxd_1xxd_2`, Where `d_1 and d_2` are the lengths of the diagonals.
⇒ `480=1/2xx48xxd_2`
⇒`d_2=(480xx2)/48`
⇒ `d_2=20 cm`
∴ Length of the other diagonal=`20cm`
(2) side=`1/2 sqrt(d_1^2-d_2^2)`
= `1/2sqrt(48^2+20^2)`
=`1/2sqrt(2304+400)`
=`1/2sqrt2704`
=`1/2xx52`
=`26 cm`
∴ Length of the side of the rhombus =`26cm`
(iii) Perimeter of the rhombus=`4xx"side"`
=`4xx26`
=`104 cm`
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