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The adjacent sides of a parallelogram ABCD measure 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram.

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Question

The adjacent sides of a parallelogram ABCD measure 34 cm and 20 cm, and the diagonal AC measures 42 cm. Find the area of the parallelogram. 

 

Sum
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Solution

Parallelogram ABCD is made up of congruent `ΔABC and ΔADC`  

Area of triangle ABC= `sqrt (s (s-a)(s-b)(s-c))` 

Thus, we have : 

`s=(a+b+c)/2` 

`s=(34+20+42)/2` 

`s=48 cm` 

Area of Δ ABC=`sqrt(48(48-34)(48-20)(48-42))` 

  =`sqrt(48xx14xx28xx6)` 

=`336 cm^2` 

Now,

Area of the parallelogram=`2xx `Area of ΔABC 

=`2xx336` 

=`672 cm^2`

 

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Chapter 15: Perimeter And Area of Plane Figures - EXERCISE 15B [Page 694]

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R.S. Aggarwal Mathematics [English] Class 10
Chapter 15 Perimeter And Area of Plane Figures
EXERCISE 15B | Q 31. | Page 694
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