Advertisements
Advertisements
Question
Subtract: 2y + z from 6z – 5y
Sum
Advertisements
Solution
6z – 5y – (2y + z) = 6z – 5y + (– 2y – z)
= 6z – 5y – 2y – z
= 6z – z – 5y – 2y
= (6 – 1)z + (– 5 – 2)y
= 5z + (– 7)y
= 5z – 7y
= – 7y + 5z
shaalaa.com
Is there an error in this question or solution?
Chapter 3: Algebra - Exercise 3.2 [Page 63]
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(4xy − 9z); (3xy − 16z)
Subtract the second expression from the first.
(14x2 + 8xy + 3y2); (26x2 − 8xy − 17y2)
Subtract the second expression from the first.
(6x2 + 7xy + 16y2); (16x2 − 17xy)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract 5x2 – 4y2 + 6y – 3 from 7x2 – 4xy + 8y2 + 5x – 3y.
One number is seven times another. If their difference is 18, find the numbers
Subtract:
3t4 – 4t3 + 2t2 – 6t + 6 from – 4t4 + 8t3 – 4t2 – 2t + 11
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
