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प्रश्न
Subtract: 2y + z from 6z – 5y
योग
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उत्तर
6z – 5y – (2y + z) = 6z – 5y + (– 2y – z)
= 6z – 5y – 2y – z
= 6z – z – 5y – 2y
= (6 – 1)z + (– 5 – 2)y
= 5z + (– 7)y
= 5z – 7y
= – 7y + 5z
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अध्याय 3: Algebra - Exercise 3.2 [पृष्ठ ६३]
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