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प्रश्न
Subtract: 13x + 12y – 5 from 27x + 5y – 43
योग
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उत्तर
27x + 5y – 43 – (13x + 12y – 5) = 27z + 5y – 43 + (– 13x – 12y + 5)
= 27x + 5y – 43 – 13x – 12y + 5
= (27 – 13)x + (5 – 12)y + (– 43) + 5
= 14x + (– 7)y + (– 38)
= 14x – 7y – 38
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