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प्रश्न
What should be subtracted from 2x3 – 3x2y + 2xy2 + 3y3 to get x3 – 2x2y + 3xy2 + 4y3?
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उत्तर
In order to get the solution, we will subtract x3 – 2x2y + 3xy2 + 4y3 from 2x3 – 3x2y + 2xy2 + 3y3
Required expression is 2x3 – 3x2y + 2xy2 + 3y3 – (x3 – 2x2y + 3xy2 + 4y3) = 2x3 – 3x2y + 2xy2 + 3y3 – x3 + 2x2y – 3xy2 – 4y3
On combining the like terms,
= 2x3 – x3 – 3x2y + 2x2y + 2xy2 – 3xy2 + 3y3 – 4y3
= x3 – x2y – xy2 – y3
So, if we subtract x3 – x2y – xy2 – y3 from 2x3 – 3x2y + 2xy2 + 3y3, then we get x3 – 2x2y + 3xy2 + 4y3.
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