Question

What should be subtracted from 2x³ – 3x²y + 2xy² + 3y³ to get x³ – 2x²y + 3xy² + 4y³?

Answer 1

In order to get the solution, we will subtract x³ – 2x²y + 3xy² + 4y³ from 2x³ – 3x²y + 2xy² + 3y³

Required expression is 2x³ – 3x²y + 2xy² + 3y³ – (x³ – 2x²y + 3xy² + 4y³) = 2x³ – 3x²y + 2xy² + 3y³ – x³ + 2x²y – 3xy² – 4y³

On combining the like terms,

= 2x³ – x³ – 3x²y + 2x²y + 2xy² – 3xy² + 3y³ – 4y³

= x³ – x²y – xy² – y³

So, if we subtract x³ – x²y – xy² – y³ from 2x³ – 3x²y + 2xy² + 3y³, then we get x³ – 2x²y + 3xy² + 4y³.