Advertisements
Advertisements
प्रश्न
To what expression must 99x3 – 33x2 – 13x – 41 be added to make the sum zero?
Advertisements
उत्तर
In order to find the solution, we will subtract 99x3 – 33x2 – 13x – 41 from 0
Required expression is 0 – (99x3 – 33x2 – 13x – 41)
= 0 – 99x3 + 33x2 + 13x + 41
= –99x3 + 33x2 + 13x + 41
So, If we add –99x3 + 33x2 + 13x + 41 to 99x3 – 33x2 – 13x – 41, then the sum is zero.
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
(6x2 + 7xy + 16y2); (16x2 − 17xy)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract: −2(xy)2 (y3 + 7x2y + 5) from 5y2 (x2y3 – 2x4y + 10x2)
One number is seven times another. If their difference is 18, find the numbers
Subtract: 4k from 12k
Subtract: 3p + 5 from p – 2q + 7
When we subtract ‘a’ from ‘−a’, we get __________
Subtract:
5a2b2c2 from –7a2b2c2
Subtract the following expressions:
–4x2y – y3 from x3 + 3xy2 – x2y
What should be subtracted from 2x3 – 3x2y + 2xy2 + 3y3 to get x3 – 2x2y + 3xy2 + 4y3?
