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प्रश्न
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
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उत्तर
We have, –ab – bc – ca – 2(ab + bc + ca)
= –ab – bc – ca – 2ab – 2bc – 2ca
On combining the like terms,
= –ab – 2ab – bc – 2bc – ca – 2ca
= –3ab – 3bc – 3ca
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संबंधित प्रश्न
Subtract the second expression from the first.
(5x + 4y + 7z); (x + 2y + 3z)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Sum of a – b + c and – a + b – c is zero
Subtract: 3p + 5 from p – 2q + 7
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Subtracting a term from a given expression is the same as adding its additive inverse to the given expression.
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
(A + B) – C
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
A + B + C
