Advertisements
Advertisements
प्रश्न
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
Advertisements
उत्तर
Required expression is
93p2 – 55p + 4 – (13p3 – 5p2 + 17p – 90)
= 93p2 – 55p + 4 – 13p3 + 5p2 – 17p + 90
On combining the like terms,
= 93p2 + 5p2 – 55p – 17p + 4 + 90 – 13p3
= 98p2 – 72p + 94 – 13p3
= –13p3 + 98p2 – 72p + 94
So, 93p2 – 55p + 4 is –13p3 + 9p2 – 72p + 94 exceed from 13p3 – 5p2 + 17p – 90.
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
(14x2 + 8xy + 3y2); (26x2 − 8xy − 17y2)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Sum of a – b + c and – a + b – c is zero
Subtract: 4k from 12k
Subtract: 13x + 12y – 5 from 27x + 5y – 43
Subtract: 3p + 5 from p – 2q + 7
Subtract – 3ab – 8 from 3ab + 8. Also, subtract 3ab + 8 from – 3ab – 8
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
What should be subtracted from 2x3 – 3x2y + 2xy2 + 3y3 to get x3 – 2x2y + 3xy2 + 4y3?
If P = –(x – 2), Q = –2(y + 1) and R = –x + 2y, find a, when P + Q + R = ax.
