Advertisements
Advertisements
प्रश्न
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
Advertisements
उत्तर
Required expression is
93p2 – 55p + 4 – (13p3 – 5p2 + 17p – 90)
= 93p2 – 55p + 4 – 13p3 + 5p2 – 17p + 90
On combining the like terms,
= 93p2 + 5p2 – 55p – 17p + 4 + 90 – 13p3
= 98p2 – 72p + 94 – 13p3
= –13p3 + 98p2 – 72p + 94
So, 93p2 – 55p + 4 is –13p3 + 9p2 – 72p + 94 exceed from 13p3 – 5p2 + 17p – 90.
APPEARS IN
संबंधित प्रश्न
Subtract the second expression from the first.
(4xy − 9z); (3xy − 16z)
Subtract: −2(xy)2 (y3 + 7x2y + 5) from 5y2 (x2y3 – 2x4y + 10x2)
Subtract:
2ab2c2 + 4a2b2c – 5a2bc2 from –10a2b2c + 4ab2c2 + 2a2bc2
Subtract the following expressions:
–7p2qr from –3p2qr
Subtract the following expressions:
–a2 – ab from b2 + ab
Subtract the following expressions:
–2a2 – 2b2 from –a2 – b2 + 2ab
Subtract the following expressions:
4.5x5 – 3.4x2 + 5.7 from 5x4 – 3.2x2 – 7.3x
Subtract the following expressions:
11 – 15y2 from y3 – 15y2 – y – 11
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
