Advertisements
Advertisements
प्रश्न
What should be subtracted from –7mn + 2m2 + 3n2 to get m2 + 2mn + n2?
Advertisements
उत्तर
In order to get solution, we will subtract m2 + 2mn + n2 from –7mn + 2m2 + 3n2
Required expression is –7mn + 2m2 + 3n2 – (m2 + 2mn + n2) = –7mn + 2m2 + 3n2 – m2 – 2mn – n2
On combining the like terms,
= –7mn – 2mn + 2m2 – m2 + 3n2 – n2
= –9mn + m2 + 2n2
So, if we subtract m2 + 2n2 – 9mn from –7mn + 2m2 + 3n2, then we get m2 + 2mn + n2.
APPEARS IN
संबंधित प्रश्न
One number is seven times another. If their difference is 18, find the numbers
Sum of a – b + c and – a + b – c is zero
When we subtract ‘a’ from ‘−a’, we get __________
Subtract:
5a2b2c2 from –7a2b2c2
Subtract:
6x2 – 4xy + 5y2 from 8y2 + 6xy – 3x2
Multiply the following:
(pq – 2r), (pq – 2r)
Subtracting a term from a given expression is the same as adding its additive inverse to the given expression.
Subtract the following expressions:
–7p2qr from –3p2qr
Subtract the following expressions:
x3y2 + 3x2y2 – 7xy3 from x4 + y4 + 3x2y2 – xy3
