Advertisements
Advertisements
Question
Subtract:
2ab + 5bc – 7ac from 5ab – 2bc – 2ac + 10abc
Advertisements
Solution
We have,
2ab + 5bc – 7ac and 5ab – 2bc – 2ac + 10abc
The required difference is given by (5ab – 2bc – 2ac + 10abc) – (2ab + 5bc – 7ac)
= 5ab – 2bc – 2ac + 10abc – 2ab – 5bc + 7ac
= (5ab – 2ab) + (–2bc – 5bc) + (–2ac + 7ac) + 10abc ...[Grouping like terms]
= 3ab – 7bc + 5ac + 10abc
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(6x2 + 7xy + 16y2); (16x2 − 17xy)
Subtract the second expression from the first.
Solve the following equation.
5m − 4 = 1
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Sum of a – b + c and – a + b – c is zero
Subtract the following expressions:
2(ab + bc + ca) from –ab – bc – ca
Subtract 9a2 – 15a + 3 from unity.
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
(A + B) – C
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
A + B + C
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
