Advertisements
Advertisements
Question
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
Advertisements
Solution
We have,
7p(3q + 7p) and 8p(2p – 7q)
The required difference is given by 8p(2p – 7q) – 7p(3q + 7p)
= 16p2 – 56pq – 21pq – 49p2
= (16p2 – 49p2) + (–56pq – 21pq) ...[Grouping like terms]
= – 33p2 + (–77pq)
= – 33p2 – 77pq
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(6x2 + 7xy + 16y2); (16x2 − 17xy)
Subtract: m + n from 3m – 7n
Subtract:
–3p2 + 3pq + 3px from 3p(– p – a – r)
Subtract the following expressions:
–a2 – ab from b2 + ab
Subtract the following expressions:
4.5x5 – 3.4x2 + 5.7 from 5x4 – 3.2x2 – 7.3x
What should be subtracted from –7mn + 2m2 + 3n2 to get m2 + 2mn + n2?
How much does 93p2 – 55p + 4 exceed 13p3 – 5p2 + 17p – 90?
Subtract 9a2 – 15a + 3 from unity.
If A = 3x2 – 4x + 1, B = 5x2 + 3x – 8 and C = 4x2 – 7x + 3, then find:
B + C – A
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
