Advertisements
Advertisements
Question
Subtract:
7p(3q + 7p) from 8p(2p – 7q)
Advertisements
Solution
We have,
7p(3q + 7p) and 8p(2p – 7q)
The required difference is given by 8p(2p – 7q) – 7p(3q + 7p)
= 16p2 – 56pq – 21pq – 49p2
= (16p2 – 49p2) + (–56pq – 21pq) ...[Grouping like terms]
= – 33p2 + (–77pq)
= – 33p2 – 77pq
APPEARS IN
RELATED QUESTIONS
Subtract the second expression from the first.
(5x + 4y + 7z); (x + 2y + 3z)
Subtract the second expression from the first.
(6x2 + 7xy + 16y2); (16x2 − 17xy)
Solve:
(7m − 5n) − (−4n − 11m)
Solve:
(11m − 12n + 3p) − (9m + 7n − 8p)
Subtract: 15q from 25q
Subtract the following expressions:
x4 + 3x3y3 + 5y4 from 2x4 – x3y3 + 7y4
What should be subtracted from –7mn + 2m2 + 3n2 to get m2 + 2mn + n2?
How much is 21a3 – 17a2 less than 89a3 – 64a2 + 6a + 16?
From the sum of x2 – y2 – 1, y2 – x2 – 1 and 1 – x2 – y2 subtract –(1 + y2).
Subtract the sum of 12ab – 10b2 – 18a2 and 9ab + 12b2 + 14a2 from the sum of ab + 2b2 and 3b2 – a2.
