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State whether the following statement is True or False: ∑p0q0+q1∑p1q0+q1×100 is Marshall-Edgeworth Price Index Number - Mathematics and Statistics

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Question

State whether the following statement is True or False:

`(sum"p"_0sqrt("q"_0 + "q"_1))/(sum"p"_1sqrt("q"_0 + "q"_1)) xx 100` is Marshall-Edgeworth Price Index Number

Options

  • True

  • False

MCQ
True or False
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Solution

False

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Construction of Index Numbers - Weighted Aggregate Method
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Chapter 2.5: Index Numbers - Q.3

RELATED QUESTIONS

Calculate Walsh’s Price Index Number.

Commodity Base Year Current Year
Price Quantity Price Quantity
L 4 16 3 19
M 6 16 8 14
N 8 28 7 32

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Commodity Base Year Current Year
Price Quantity Price Quantity
I 10 12 20 9
II 20 4 25 8
III 30 13 40 27
IV 60 29 75 36

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`(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx (sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is Dorbish-Bowley’s Price Index Number.


State whether the following is True or False :

`sqrt(("p"_1"q"_0)/(sum"p"_0"q"_0)) xx sqrt((sum"p"_1"q"_1)/(sum"p"_0"q"_1)) xx 100` is Fisher’s Price Index Number.


Solve the following problem :

Calculate Dorbish-Bowley’s Price Index Number for the following data.

Commodity Base Year Current Year
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If find x is Walsh’s Price Index Number is 150 for the following data

Commodity Base Year Current Year
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Solve the following problem :

If `sum"p_"0"q"_0 = 120, sum "p"_0"q"_1 = 160, sum "p"_1"q"_1 = 140, and sum "p"_1"q"+0` = 200, find Laspeyre’s, Paasche’s Dorbish-Bowley’s and Marshall Edgeworth’s Price Index Number.


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Given that `sum "p"_0"q"_0 = 130, sum "p"_1"q"_1 = 140, sum "p"_0"q"_1 = 160, and sum "p"_1"q"_0 = 200`, find Laspeyre’s, Paasche’s, Dorbish-Bowley’s, and Marshall-Edgeworth’s Price Index Numbers.


Choose the correct alternative:

Price Index Number by using Weighted Aggregate Method is given by


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The formula P01 = `(sum"p"_1"q"_0)/(sum"p"_0"q"_0) xx 100` is for


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Commodity Base Year Current Year
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Given the following table, find Walsh’s Price Index Number by completing the activity.

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I 20 9 30 4 36 `square` `square` 180
II 10 5 50 5 `square` 5 50 `square`
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IV 30 4 20 1 `square` 2 `square` 40
Total     390 `square`

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= `510/square xx 100`

= `square`


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