English
Tamil Nadu Board of Secondary EducationHSC Science Class 12

State Ampere’s circuital law. - Physics

Advertisements
Advertisements

Question

State Ampere’s circuital law.

Short/Brief Note
Advertisements

Solution

The line integral of the magnetic field over a closed-loop is μ0 times the net current enclosed by loop.

`oint_"C" vec"B" * vec"l" = mu_circ "I"_"enclosed"`

`"I"_"enclosed"` → net current in the closed-loop C.

shaalaa.com
  Is there an error in this question or solution?
Chapter 3: Magnetism and magnetic effects of electric current - Evaluation [Page 191]

APPEARS IN

Samacheer Kalvi Physics - Volume 1 and 2 [English] Class 12 TN Board
Chapter 3 Magnetism and magnetic effects of electric current
Evaluation | Q II. 8. | Page 191

RELATED QUESTIONS

Write Maxwell's generalization of Ampere's circuital law. Show that in the process of charging a capacitor, the current produced within the plates of the capacitor is `I=varepsilon_0 (dphi_E)/dt,`where ΦE is the electric flux produced during charging of the capacitor plates.


State Ampere’s circuital law.


Obtain an expression for magnetic induction along the axis of the toroid.


A solid wire of radius 10 cm carries a current of 5.0 A distributed uniformly over its cross section. Find the magnetic field B at a point at a distance (a) 2 cm (b) 10 cm and (c) 20 cm away from the axis. Sketch a graph B versus x for 0 < x < 20 cm. 


Sometimes we show an idealised magnetic field which is uniform in a given region and falls to zero abruptly. One such field is represented in figure. Using Ampere's law over the path PQRS, show that such a field is not possible. 


Ampere’s circuital law states that ______.

Which of the following is the correct definition of ampere?

A solenoid of length 0.6 m has a radius of 2 cm and is made up of 600 turns If it carries a current of 4 A, then the magnitude of the magnetic field inside the solenoid is:


Read the following paragraph and answer the questions.

Consider the experimental set-up shown in the figure. This jumping ring experiment is an outstanding demonstration of some simple laws of Physics. A conducting non-magnetic ring is placed over the vertical core of a solenoid. When current is passed through the solenoid, the ring is thrown off.

  1. Explain the reason for the jumping of the ring when the switch is closed in the circuit.
  2. What will happen if the terminals of the battery are reversed and the switch is closed? Explain.
  3. Explain the two laws that help us understand this phenomenon.

The given figure shows a long straight wire of a circular cross-section (radius a) carrying steady current I. The current I is uniformly distributed across this cross-section. Calculate the magnetic field in the region r < a and r > a.

 


Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×