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Question
Solve the previous problem if the lead piece is fastened on the top surface of the block and the block is to float with its upper surface just dipping into water.
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Solution
Given:
Mass of wood, mw = 200 g
Specific gravity of wood, ρW = 0.8 gm/cc
Specific gravity of lead, ρPB= 11.3 gm/cc
\[\text{ We know: }\]
\[\text{ Mg = w} \]
\[\text{ Thus, we have: } \]
\[( \text{m}_\text{w} + \text{m}_{\text{pb}} )\text{g} = \text{V}_\text{w} \times \rho \times g\] \[ [\rho = \text{ Density of water }]\]
\[ \Rightarrow 200 + \text{m}_{\text{pb}} = \frac{200}{0 . 8} \times 1\]
\[ \Rightarrow \text{m}_{\text{pb}} = 250 - 200 = 50 \text{gm}\]
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