Advertisements
Advertisements
Question
Solve the following quadratic equation using formula method only :
16x2 = 24x + 1
Advertisements
Solution
16x2 = 24x + 1
16x2 - 24x - 1 = 0
`"x"^2 - 3/2 "x" - 1/16 = 0`
a = 1 ; b = `-3/2` ; c =`- 1/16`
D = b2 - 4ac
`= (- 3/2)^2 - 4(1)(-1/16)`
`= 9/4 + 1/4`
`= 10/4`
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(- (- 3/2) ± sqrt (10/4))/(2 xx 1)`
x = `(3 + sqrt 10)/4` , x = `(3 - sqrt(10))/4`
APPEARS IN
RELATED QUESTIONS
Determine the nature of the roots of the following quadratic equation:
2(a2 + b2)x2 + 2(a + b)x + 1 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
2kx2 - 40x + 25 = 0
If the roots of the equations ax2 + 2bx + c = 0 and `bx^2-2sqrt(ac)x+b = 0` are simultaneously real, then prove that b2 = ac.
Find the value of the discriminant in the following quadratic equation :
10 x - `1/x` = 3
Discuss the nature of the roots of the following quadratic equations : `2sqrt(3)x^2 - 5x + sqrt(3)` = 0
Without solving the following quadratic equation, find the value of ‘p’ for which the given equations have real and equal roots: x2 + (p – 3)x + p = 0.
Mohan and Sohan solve an equation. In solving Mohan commits a mistake in constant term and finds the roots 8 and 2. Sohan commits a mistake in the coefficient of x. The correct roots are:
If the roots of equation 3x2 + 2x + (p + 2) (p – 1) = 0 are of opposite sign then which of the following cannot be the value of p?
Find whether the following equation have real roots. If real roots exist, find them.
8x2 + 2x – 3 = 0
If one root of equation (p – 3) x2 + x + p = 0 is 2, the value of p is ______.
