Advertisements
Advertisements
प्रश्न
Solve the following quadratic equation using formula method only :
16x2 = 24x + 1
Advertisements
उत्तर
16x2 = 24x + 1
16x2 - 24x - 1 = 0
`"x"^2 - 3/2 "x" - 1/16 = 0`
a = 1 ; b = `-3/2` ; c =`- 1/16`
D = b2 - 4ac
`= (- 3/2)^2 - 4(1)(-1/16)`
`= 9/4 + 1/4`
`= 10/4`
x = `(- "b" ± sqrt ("b"^2 - 4 "ac"))/(2a)`
x = `(- (- 3/2) ± sqrt (10/4))/(2 xx 1)`
x = `(3 + sqrt 10)/4` , x = `(3 - sqrt(10))/4`
APPEARS IN
संबंधित प्रश्न
Solve the following quadratic equation by using formula method: 5m2 + 5m – 1 = 0
If x=−`1/2`, is a solution of the quadratic equation 3x2+2kx−3=0, find the value of k
Find the value of p for which the quadratic equation (2p + 1)x2 − (7p + 2)x + (7p − 3) = 0 has equal roots. Also find these roots.
Without solving, examine the nature of roots of the equation 2x2 + 2x + 3 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
kx2 + 4x + 1 = 0
Find the values of k for which the roots are real and equal in each of the following equation:
2kx2 - 40x + 25 = 0
Solve x2/3 + x1/3 - 2 = 0.
Find the nature of the roots of the following quadratic equations: `x^2 - 2sqrt(3)x - 1` = 0 If real roots exist, find them.
If the root of the given quadratic equation are real and equal, then find the value of ‘k’ X2 + 2X + k = 0.
State whether the following quadratic equation have two distinct real roots. Justify your answer.
`2x^2 - 6x + 9/2 = 0`
