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∫ Sin 5 X D X - Mathematics

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Question

\[\int \sin^5 x \text{ dx }\]
Sum
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Solution

∫ sin5 x dx
= ​∫ sin4 x . sin x dx
= ∫ (1 – cos2 x)2 sin x dx

= ∫ (1 – cos4 x – 2 cos2 x) sin x dx
Let cos x = t
⇒ – sin x dx = dt

⇒ sin x dx = – dt
Now, ∫ (1 – cos4 x – 2 cos2 x) sin x dx
=–​∫ (1 + t4 – 2t2) dt

\[= - \left[ t + \frac{t^5}{5} - \frac{2 t^3}{3} \right] + C\]
\[ = - t - \frac{t^5}{5} + \frac{2 t^3}{3} + C\]
\[ = - \cos x + \frac{2}{3} \cos^3 x - \frac{\cos^5 x}{5} + C\]

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Chapter 19: Indefinite Integrals - Exercise 19.12 [Page 73]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.12 | Q 2 | Page 73

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