English

∫ Tan X Sec X + Tan X D X - Mathematics

Advertisements
Advertisements

Question

\[\int\frac{\tan x}{\sec x + \tan x} dx\]
Sum
Advertisements

Solution

\[\int\frac{\tan x}{\sec x + \tan x}dx\]
\[ = \int\frac{\tan x}{\left( \sec x + \tan x \right)} \times \left( \frac{\sec x - \tan x}{\sec x - \tan x} \right)dx\]
\[ = \int\frac{\tan x \left( \sec x - \tan x \right)}{\left( \sec^2 x - \tan^2 x \right)}dx\]
\[ = \int\left( \frac{\sec x \tan x - \tan^2 x}{1} \right)dx\]
\[ = \int\text{sec x }\text{tan  x  dx} - \int\left( se c^2 x - 1 \right)dx\]
\[ = \sec x - \tan x + x + C\]

shaalaa.com
  Is there an error in this question or solution?
Chapter 19: Indefinite Integrals - Exercise 19.02 [Page 15]

APPEARS IN

RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
Exercise 19.02 | Q 31 | Page 15

Video TutorialsVIEW ALL [1]

RELATED QUESTIONS

\[\int \left( \tan x + \cot x \right)^2 dx\]

\[\int\frac{\left( x^3 + 8 \right)\left( x - 1 \right)}{x^2 - 2x + 4} dx\]

\[\int \sin^2 \frac{x}{2} dx\]

`  ∫  sin 4x cos  7x  dx  `

Integrate the following integrals:

\[\int\text { sin  x  cos  2x     sin 3x   dx}\]

\[\int\frac{\text{sin} \left( x - \alpha \right)}{\text{sin }\left( x + \alpha \right)} dx\]

\[\int\frac{\cos 4x - \cos 2x}{\sin 4x - \sin 2x} dx\]

\[\int\frac{\sin 2x}{\left( a + b \cos 2x \right)^2} dx\]

\[\int\frac{x \sin^{- 1} x^2}{\sqrt{1 - x^4}} dx\]

\[\int\left( \frac{x + 1}{x} \right) \left( x + \log x \right)^2 dx\]

` ∫    x   {tan^{- 1} x^2}/{1 + x^4} dx`

` ∫    \sqrt{tan x}     sec^4  x   dx `


\[\int {cosec}^4  \text{ 3x } \text{ dx } \]

\[\int\frac{1}{x^2 - 10x + 34} dx\]

\[\int\frac{\left( 3 \sin x - 2 \right) \cos x}{5 - \cos^2 x - 4 \sin x} dx\]

\[\int\frac{x^3}{x^4 + x^2 + 1}dx\]

\[\int\frac{x^2 + x + 1}{x^2 - x} dx\]

\[\int\frac{x^2}{x^2 + 7x + 10} dx\]

\[\int\frac{2x + 1}{\sqrt{x^2 + 4x + 3}} \text{ dx }\]

\[\int\frac{5x + 3}{\sqrt{x^2 + 4x + 10}} \text{ dx }\]

\[\int x\left( \frac{\sec 2x - 1}{\sec 2x + 1} \right) dx\]

\[\int\frac{x^2 \sin^{- 1} x}{\left( 1 - x^2 \right)^{3/2}} \text{ dx }\]

\[\int e^x \left( \cot x + \log \sin x \right) dx\]

\[\int\left\{ \tan \left( \log x \right) + \sec^2 \left( \log x \right) \right\} dx\]

\[\int\frac{\sqrt{16 + \left( \log x \right)^2}}{x} \text{ dx}\]

\[\int(2x + 5)\sqrt{10 - 4x - 3 x^2}dx\]

\[\int\frac{2x}{\left( x^2 + 1 \right) \left( x^2 + 3 \right)} dx\]

\[\int\frac{x^2 + 1}{\left( x - 2 \right)^2 \left( x + 3 \right)} dx\]

\[\int\frac{3x + 5}{x^3 - x^2 - x + 1} dx\]

\[\int\frac{\sin x}{3 + 4 \cos^2 x} dx\]

\[\int\frac{x^2}{\left( x - 1 \right)^3} dx\]

\[\int\frac{1}{4 x^2 + 4x + 5} dx\]

\[\int\sqrt{\text{ cosec  x} - 1} \text{ dx }\]

\[\int \sec^6 x\ dx\]

\[\int\frac{1}{\sec x + cosec x}\text{  dx }\]

\[\int\sqrt{x^2 - a^2} \text{ dx}\]

\[\int \sec^{- 1} \sqrt{x}\ dx\]

\[\int\frac{\cot x + \cot^3 x}{1 + \cot^3 x} \text{ dx}\]

\[\int\frac{x^2 + 1}{x^2 - 5x + 6} \text{ dx }\]
 

Share
Notifications

Englishहिंदीमराठी


      Forgot password?
Use app×