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∫ Cos 2 X − 1 Cos 2 X + 1 D X = - Mathematics

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Question

\[\int\frac{\cos 2x - 1}{\cos 2x + 1} dx =\]

Options

  • tan x − x + C

  • x + tan x + C

  • x − tan x + C

  • − x − cot x + C

MCQ
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Solution

x − tan x + C

\[\int\left( \frac{\cos 2x - 1}{\cos 2x + 1} \right)dx\]

\[ = \int\left( \frac{1 - 2 \sin^2 x - 1}{2 \cos^2 x - 1 + 1} \right)dx\]

\[ = - \int \tan^2 x dx\]

\[ = - \int\left( \sec^2 x - 1 \right)dx\]

\[ = \int\left( 1 - \sec^2 x \right)dx\]

\[ = x - \tan x + C\]

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Chapter 19: Indefinite Integrals - MCQ [Page 202]

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RD Sharma Mathematics [English] Class 12
Chapter 19 Indefinite Integrals
MCQ | Q 30 | Page 202

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