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∫ Cos 2 X − 1 Cos 2 X + 1 D X = - Mathematics

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प्रश्न

\[\int\frac{\cos 2x - 1}{\cos 2x + 1} dx =\]

विकल्प

  • tan x − x + C

  • x + tan x + C

  • x − tan x + C

  • − x − cot x + C

MCQ
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उत्तर

x − tan x + C

\[\int\left( \frac{\cos 2x - 1}{\cos 2x + 1} \right)dx\]

\[ = \int\left( \frac{1 - 2 \sin^2 x - 1}{2 \cos^2 x - 1 + 1} \right)dx\]

\[ = - \int \tan^2 x dx\]

\[ = - \int\left( \sec^2 x - 1 \right)dx\]

\[ = \int\left( 1 - \sec^2 x \right)dx\]

\[ = x - \tan x + C\]

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  क्या इस प्रश्न या उत्तर में कोई त्रुटि है?
अध्याय 19: Indefinite Integrals - MCQ [पृष्ठ २०२]

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आरडी शर्मा Mathematics [English] Class 12
अध्याय 19 Indefinite Integrals
MCQ | Q 30 | पृष्ठ २०२

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