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Question
Simplify: `"b"("2b" - 1/"b") - "2b"("b" - 1/"b")`
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Solution
`"b"("2b" - 1/"b") - "2b"("b" - 1/"b")`
`= "b" xx "2b" - "b" xx 1/"b" - "2b" xx "b" + "2b" xx 1/"b"`
= 2b2 - 1 - 2b2 + 2
= 2b2 - 2b2 - 1 + 2
= 1
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