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Question
Show the number √7 on the number line.
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Solution
To represent √7 on the number line, use the following construction:
- Draw a number line and mark the points O(0), A(2), and B(3).
- At point A, draw a perpendicular line AC of length √3 units.
- Join O to C. By the Pythagorean theorem,
`OC = sqrt(2^2 + (sqrt3)^2)`
`=sqrt(4+3)`
`=sqrt7` - With O as the centre and radius OC, draw an arc that cuts the number line at point P.
- The point P represents the number √7 on the number line.
Since √7 ≈ 2.646, it lies between 2 and 3 on the number line.
RELATED QUESTIONS
Show the following numbers on a number line. Draw a separate number line for each example.
(1)`3/2 , 5/2 , -3/2`
(2)`7/5 , (-2)/5 , (-4)/5`
(3) `(-5)/8 , 11/8`
(4)`13/10 , (-17)/10`
Show the following numbers on a number line. Draw a separate number line for the example.
`3/2 , 5/2 , -3/2`
Show the following numbers on a number line. Draw a separate number line for the example.
`(-5)/8 , 11/8`
Evaluate:
`5/9 + (-7)/6`
Draw a number line and represent the following rational numbers on it
`9/4`
Draw a number line and represent the following rational numbers on it
`(-8)/3`
The rational number `7/(-4)` lies to the right of zero on the number line.
The rational numbers `1/2` and –1 are on the opposite sides of zero on the number line.
The rational numbers `1/2` and `- 5/2` are on the opposite sides of 0 on the number line.
The rational number `(-3)/4` lies to the right of zero on the number line.
