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प्रश्न
Show the number √7 on the number line.
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उत्तर
To represent √7 on the number line, use the following construction:
- Draw a number line and mark the points O(0), A(2), and B(3).
- At point A, draw a perpendicular line AC of length √3 units.
- Join O to C. By the Pythagorean theorem,
`OC = sqrt(2^2 + (sqrt3)^2)`
`=sqrt(4+3)`
`=sqrt7` - With O as the centre and radius OC, draw an arc that cuts the number line at point P.
- The point P represents the number √7 on the number line.
Since √7 ≈ 2.646, it lies between 2 and 3 on the number line.
संबंधित प्रश्न
Show the following numbers on a number line. Draw a separate number line for the example.
`3/2 , 5/2 , -3/2`
Evaluate:
`5/9 + 3/-4`
Draw a number line and mark
`3/4, 7/4, (-3)/4 and (-7)/4` on it.
Draw a number line and mark
`2/3, (-8)/3, 7/3, (-2)/3 and -2`
Draw a number line and represent the following rational numbers on it
`(-17)/(-5)`
The rational number `57/23` lies to the left of zero on the number line.
On a number line, `4/3` is to the ______ of zero (0).
The rational number `(-3)/4` lies to the right of zero on the number line.
Find a rational number exactly halfway between:
`1/6` and `1/9`
Find a rational number exactly halfway between:
`5/(-13)` and `(-7)/9`
