Advertisements
Advertisements
Question
Separate 178 into two parts so that the first part is 8 less than twice the second part.
Advertisements
Solution
Let first part = x
Second part = 178 – x
According to the problem :
First Part = 8 less than twice the second part
x = 2(178 – x) – 8
⇒ x = 356 – 2x – 8
⇒ x+2x = 356 – 8
⇒ 3x = 348
⇒ x = 116
First Part = 116
⇒ Second Part = 178 – x = 178 – 116 = 62
First Part = 116
⇒ Second Part = 62
Alternative Method :
Let Second part = x
First part = 2x – 8
According to the problem :
x + 2x – 8 = 178
⇒ x + 2x = 178 + 8
⇒ 3x = 186
⇒ x = 62
First part = 2x – 8 = 2 x 62 – 8 = 124 – 8 = 116
First part = 116
Second part = 62
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
15 + x = 5x + 3
Solve the following equation:
`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`
Solve: `(4-3"x")/5 + (7 - "x")/3 + 4 1/3 = 0` Hence, find the value of 'p', if 3p - 2x + 1 = 0
Fifteen less than 4 times a number is 9. Find the number.
A’s salary is same as 4 times B’s salary. If together they earn Rs.3,750 a month, find the salary of each.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
Solve:
`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`
Solve: `("9x" + 7)/2 - ("x" - ("x" - 2)/7) = 36`
The sum of two numbers is 405 and their ratio is 8 : 7. Find the numbers.
Solve the following inequalities
4n + 7 ≥ 3n + 10, n is an integer
