Advertisements
Advertisements
Question
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
Advertisements
Solution
Ratio in the present ages of A and B = 7 : 5
Let age of A = 7x years
Let age of B = 5x years
10 years hence,
Then age of A = 7x + 10 years
and age of B = 5x + 10 years
According to the condition,
By crossing multiplication
7(7x + 10) = 9(5x + 10)
⇒ 49x + 70 = 45x + 90
⇒ 49x – 45x = 90 – 70
⇒ 4x = 20
⇒ x = 5
Present age of A = 7x = 7 x 5 = 35 years
and present age of B = 5x = 5 x 5 = 25 years
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
`1/("x" - 1) - 1/"x" = 1/("x" + 3) - 1/("x" + 4)`
Solve:
`5x − (4x + (5x - 4)/7) = (4x - 14)/3`
Five less than 3 times a number is -20. Find the number.
The sum of three consecutive odd numbers is 57. Find the numbers.
Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
Solve:
`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`
Solve: `2/"5x" - 5/"3x" = 1/15`
Solve: `("x" + 2)/3 - ("x" + 1)/5 = ("x" - 3)/4 - 1`
Given that x ≥ y. Fill in the blank with suitable inequality sign
x – y `square` 0
Linear inequation has almost one solution
