Advertisements
Advertisements
प्रश्न
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
Advertisements
उत्तर
Ratio in the present ages of A and B = 7 : 5
Let age of A = 7x years
Let age of B = 5x years
10 years hence,
Then age of A = 7x + 10 years
and age of B = 5x + 10 years
According to the condition,
By crossing multiplication
7(7x + 10) = 9(5x + 10)
⇒ 49x + 70 = 45x + 90
⇒ 49x – 45x = 90 – 70
⇒ 4x = 20
⇒ x = 5
Present age of A = 7x = 7 x 5 = 35 years
and present age of B = 5x = 5 x 5 = 25 years
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
20 = 6 + 2x
Solve the following equation:
`1/("x" - 1) - 1/"x" = 1/("x" + 3) - 1/("x" + 4)`
Solve:
`5x − (4x + (5x - 4)/7) = (4x - 14)/3`
Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`
The numerator of a fraction is 5 less than its denominator. If 3 is added to the numerator, and denominator both, the fraction becomes`4/5`. Find the original fraction.
Linear inequation has almost one solution
When x is an integer, the solution set for x ≤ 0 are −1, −2, ...
Solve the following inequation
x – 6 < 1, where x is a natural number
Solve the following inequation
2a + 3 ≤ 13, where a is a whole number
Solve the following inequation
6x – 7 ≥ 35, where x is an integer
