Advertisements
Advertisements
प्रश्न
Solve:
`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`
Advertisements
उत्तर
`"x" + 2/6 - 11 - "x"/3 - 1/4 = 3"x" - 4/12`
`=> ("x" + 2)/6 - (4(11 - x) - 1 xx 3)/12 = (3"x" - 4)/12`
`=> ("x" + 2)/6 - (44 + 4x + 3)/12 = (3"x" - 4)/12`
`=> (2("x" + 2) - 41 + 4"x")/12 = (3"x" - 4)/12`
`=> (2"x" + 4 - 41 + 4"x")/12 = (3"x" - 4)/12`
`=> (6"x" - 37)/12 = (3"x" - 4)/12`
⇒ 12(6x − 37) = 12(3x − 4)
⇒ 72x − 444 = 36x − 48
⇒ 72x − 36x = −48 + 444
⇒ 36x = 396
⇒ x = `396/36 = 11`
∴ x = 11
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
`(3"x")/("x" + 6) - "x"/("x" + 5) = 2`
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Solve:
13(x − 4) - 3(x − 9) − 5(x + 4) = 0
Solve: `"x" + 7 - "8x"/3 = "17x"/6 - "5x"/8`
After 12 years, I shall be 3 times as old as 1 was 4 years ago. Find my present age.
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
Given that x ≥ y. Fill in the blank with suitable inequality sign
x – y `square` 0
Solve the following inequalities
4n + 7 ≥ 3n + 10, n is an integer
