Advertisements
Advertisements
प्रश्न
Solve the following inequation
2a + 3 ≤ 13, where a is a whole number
Advertisements
उत्तर
2a + 3 ≤ 13
Subtracting 3 from both the sides
2a + 3 – 3 ≤ 13 – 3
2a ≤ 10
Dividing both the side by 2
`(2"a")/2` ≤ `10/2`
a ≤ 5
Since the solutions belong to the set of whole numbers that are less than or equal to 5 we take the values of a as 0, 1, 2, 3, 4 and 5
APPEARS IN
संबंधित प्रश्न
Solve: `"2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6` Hence, find the value of 'a', if `1/"a" + 5"x" = 8`
Solve: 0.25 + `1.95/"x" = 0.9`
Separate 178 into two parts so that the first part is 8 less than twice the second part.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
Solve: `(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
After 12 years, I shall be 3 times as old as 1 was 4 years ago. Find my present age.
The numerator of a fraction is 5 less than its denominator. If 3 is added to the numerator, and denominator both, the fraction becomes`4/5`. Find the original fraction.
Solve the following inequation
x – 6 < 1, where x is a natural number
Solve the following inequalities
−13 ≤ 5x + 2 ≤ 32, x is an integer
