Advertisements
Advertisements
प्रश्न
Solve:
`(x + 2)/6 - ((11 - x)/3 - 1/4) = (3x - 4)/12`
Advertisements
उत्तर
`"x" + 2/6 - 11 - "x"/3 - 1/4 = 3"x" - 4/12`
`=> ("x" + 2)/6 - (4(11 - x) - 1 xx 3)/12 = (3"x" - 4)/12`
`=> ("x" + 2)/6 - (44 + 4x + 3)/12 = (3"x" - 4)/12`
`=> (2("x" + 2) - 41 + 4"x")/12 = (3"x" - 4)/12`
`=> (2"x" + 4 - 41 + 4"x")/12 = (3"x" - 4)/12`
`=> (6"x" - 37)/12 = (3"x" - 4)/12`
⇒ 12(6x − 37) = 12(3x − 4)
⇒ 72x − 444 = 36x − 48
⇒ 72x − 36x = −48 + 444
⇒ 36x = 396
⇒ x = `396/36 = 11`
∴ x = 11
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
15 + x = 5x + 3
Solve the following equation:
`(3"x" + 2)/("x" - 6) = -7`
Solve:
`5x − (4x + (5x - 4)/7) = (4x - 14)/3`
Separate 178 into two parts so that the first part is 8 less than twice the second part.
Six more than one-fourth of a number is two-fifth of the number. Find the number.
Three consecutive whole numbers are such that if they be divided by 5, 3 and 4 respectively; the sum of the quotients is 40. Find the numbers.
Solve: `1/3"x" - 6 = 5/2`
Solve: `("9x" + 7)/2 - ("x" - ("x" - 2)/7) = 36`
Solve the following inequation
x ≤ 7, where x is a natural number
Solve the following inequalities
−13 ≤ 5x + 2 ≤ 32, x is an integer
