Advertisements
Advertisements
प्रश्न
An artist can spend any amount between ₹ 80 to ₹ 200 on brushes. If cost of each brush is ₹ 5 and there are 6 brushes in each packet, then how many packets of brush can the artist buy?
Advertisements
उत्तर
Given the artist can spend any amount between ₹ 80 to ₹ 200
Let the number of packets of brush he can buy be x
Given cost of 1 brush = ₹ 5
Cost of 1 packet brush (6 brushes) = ₹ 5 × 6 = ₹ 30
∴ Cost of x packets of brushes = 30x
∴ The inequation becomes 80 < 30x < 200
Dividing throughout by 30 we get `80/30` < `(30x)/30` < `200/30`
`8/3` < x < `20/5`,
`2 2/3` < x < `6 2/3`
brush packets cannot get in fractions.
∴ The artist can buy 3 < x < 6 packets of brushes,
or x = 3, 4, 5 and 6 packets of brushes.
APPEARS IN
संबंधित प्रश्न
Solve the following equation:
20 = 6 + 2x
Solve: `"2x"/3 - ("x" - 1)/6 + ("7x" - 1)/4 = 2 1/6` Hence, find the value of 'a', if `1/"a" + 5"x" = 8`
A number decreased by 30 is the same as 14 decreased by 3 times the number; Find the number.
The difference of two numbers is 3 and the difference of their squares is 69. Find the numbers.
Solve: `"x" + 7 - "8x"/3 = "17x"/6 - "5x"/8`
Solve: `("x" + 2)/3 - ("x" + 1)/5 = ("x" - 3)/4 - 1`
Solve: `("6x" + 1)/2 + 1 = ("7x" - 3)/3`
The sum of two numbers is 405 and their ratio is 8 : 7. Find the numbers.
The ages of A and B are in the ratio 7 : 5. Ten years hence, the ratio of their ages will be 9 : 7. Find their present ages.
When x is an integer, the solution set for x ≤ 0 are −1, −2, ...
