Advertisements
Advertisements
Question
An artist can spend any amount between ₹ 80 to ₹ 200 on brushes. If cost of each brush is ₹ 5 and there are 6 brushes in each packet, then how many packets of brush can the artist buy?
Advertisements
Solution
Given the artist can spend any amount between ₹ 80 to ₹ 200
Let the number of packets of brush he can buy be x
Given cost of 1 brush = ₹ 5
Cost of 1 packet brush (6 brushes) = ₹ 5 × 6 = ₹ 30
∴ Cost of x packets of brushes = 30x
∴ The inequation becomes 80 < 30x < 200
Dividing throughout by 30 we get `80/30` < `(30x)/30` < `200/30`
`8/3` < x < `20/5`,
`2 2/3` < x < `6 2/3`
brush packets cannot get in fractions.
∴ The artist can buy 3 < x < 6 packets of brushes,
or x = 3, 4, 5 and 6 packets of brushes.
APPEARS IN
RELATED QUESTIONS
Solve the following equation:
`1/("x - 1") + 2/("x" - 2) = 3/("x" - 3)`
Separate 178 into two parts so that the first part is 8 less than twice the second part.
A man’s age is three times that of his son, and in twelve years he will be twice as old as his son would be. What are their present ages.
The present age of a man is twice that of his son. Eight years hence, their ages will be in the ratio 7 : 4. Find their present ages
Solve: `(3"x" - 2)/3 + (2"x" + 3)/2 = "x" + 7/6`
The numerator of a fraction is 5 less than its denominator. If 3 is added to the numerator, and denominator both, the fraction becomes`4/5`. Find the original fraction.
Solve the following inequation
x ≤ 7, where x is a natural number
Solve the following inequation
x – 6 < 1, where x is a natural number
Solve the following inequation
2a + 3 ≤ 13, where a is a whole number
Solve the following inequalities
6(x + 6) ≥ 5(x – 3), x is a whole number
