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Maharashtra State BoardSSC (English Medium) 10th Standard

Read this activity and answer the following questions. 1. Take three spheres of iron, copper and lead. the lead of equal mass. 2. Put all the three spheres in boiling water in the beaker for some

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Question

Read this activity and answer the following questions.

  1. Take three spheres of iron, copper and lead. the lead of equal mass.
  2. Put all the three spheres in boiling water in the beaker for some time.
  3. Take the three spheres out of the water.
  4. All the spheres will be at a temperature 100 °C.
  5. Put them immediately on the thick slab of wax.
  6. Note, the depth that each of the sphere goes into the wax.

Questions:

  1. Which property is determined from this activity?
  2. Give name to that property.
  3. Explain the term principal of heat exchange with the help of this activity.
Answer in Brief
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Solution

  1. Property which determines the amount of heat absorbed by a sphere is different for the three spheres is ascertain from this activity.
  2. This property is called the specific heat capacity.
  3. The sphere that absorbs more heat from water supplies more heat to wax causing more melting of wax and going deeper in wax obeying the principle of heat exchange which states that; In an isolated system, Heat lost by hot object = Heat gained by cold object.
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Chapter 5: Heat - Answer the Following

RELATED QUESTIONS

Given below are observations on molar specific heats at room temperature of some common gases.

Gas

Molar specific heat (Cv)

(cal mol–1 K–1)

Hydrogen 4.87
Nitrogen 4.97
Oxygen 5.02
Nitric oxide 4.99
Carbon monoxide 5.01
Chlorine 6.17

The measured molar specific heats of these gases are markedly different from those for monatomic gases. Typically, molar specific heat of a monatomic gas is 2.92 cal/mol K. Explain this difference. What can you infer from the somewhat larger (than the rest) value for chlorine?


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Given: Specific heat capacity of copper = 0.4 Jg-1 °C-1

The Specific heat capacity of water = 4.2 Jg-1 °C-1

The Specific latent heat of fusion ice = 336 Jg-1


The temperature of 170 g of water at 50°C is lowered to 5°C by adding a certain amount of ice to it. Find the mass of ice added.

Given: Specific heat capacity of water = 4200 J kg-1 °C-1 and specific latent heat of ice = 336000 J kg-1.


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